Embibe Experts Solutions for Chapter: Friction, Exercise 1: Exercise 1

$O$ is a point at the bottom of a rough plane inclined at an angle $\alpha$ to the horizontal. Coefficient of friction between $AB$ is $\frac{\tan \alpha }{2}$ and between $BO$ is $\frac{3 \tan \alpha }{2}.\mathrm{B}$ is the mid-point of $AO.$ A block is released from rest at $A.$ Then identify which graphs are correct during motion of block from point $A$ to $O$ taking direction down the incline plane as positive:

In given diagram what is the minimum value of a horizontal external force $F$ on Block $\text{'}A\text{'}$ so that block $\text{'}B\text{'}$ will slide on ground is:

In the given diagram what is the minimum force $\text{'}F\text{'}$ required, so that block $\text{'}A\text{'}$ will slip on block $\text{'}B\text{'}$?

With reference to the figure shown, if the coefficient of friction at the surfaces is $0.42,$ then the force required to pull out the $6.0 \mathrm{kg}$ block with an acceleration of $1.50 \mathrm{m} {\mathrm{s}}^{-2}$ will be:

Two blocks $A$ and $B$ are as shown in figure. The minimum horizontal force $F$ applied on block $\text{'}B\text{'}$ for which slipping begins at $\text{'}B\text{'}$ and ground is:

A block of mass $m$ is lying on a wedge having inclination angle $\alpha ={\tan }^{-1}\left(\frac{1}{5}\right)$. Wedge is moving with a constant acceleration $a=2 \mathrm{m} {\mathrm{s}}^{-2}$ horizontally. The minimum value of coefficient of friction $\mu$, so that $m$ remains stationary with respect to wedge is:

Find the maximum horizontal force $F$ which can be applied such that sliding does not occur between $A$ and $B.$

Two bodies placed on a wedge kept fixed on a horizontal surface as shown in figure are separated by a spring. They are in equilibrium by a force of $600 \mathrm{N}$ applied on $A$. There is no friction between $B$ and inclined plane and $\mu$ is coefficient of friction between $A$ and inclined plane then $\left(g=10 \mathrm{m} {\mathrm{s}}^{-2}\right)$